The sum of seven consecutive even integers is s. Then, in terms of s, the greatest of these integers is
Let the seven even numbers be 2a, 2a+2, 2a+4, 2a+6,2a+8,2a+10,2a+12
There sum is 14a+42=s or 14(a+3)=s or a= s/14-3
Substitute for a in 2a+12 we get s+42/7
hope it helps. Thanks
Create a FREE account and get: