Directions for the next 2 questions:
For a real number x, let
$$f(x) = 1/(1+x),$$ if $$x$$ is non-negative
$$f(x) = 1+x,$$ if $$x$$ is negative
$$f^n(x) = f(f^{n-1}(x)), n = 2, 3.....$$
r is an integer 2. Then, what is the value of $$f^{r-1}(-r) + f^r(-r) + f^{r+1}(-r)$$?
f(-2) = -1
$$f^2(-2)$$ = f(f(-2)) = f(-1) = 0
$$f^3(-2)$$ = f(f(-2)) = f(0) = 1
So, sum = 0
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