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If the system of equations $$4x + 6y = 11, 2x + ay = 7$$ has no solution, then the value of a is
Given: $$4x + 6y = 11, 2x + ay = 7$$ have no solution.
For a system of linear equations $$a_1x + b_1y = c_1$$ and $$a_2x + b_2y = c_2$$ to have no solution,
$$\dfrac{a_1}{a_2} = \dfrac{b_1}{b_2} \neq \dfrac{c_1}{c_2}$$
Comparing with the given equations,
$$\dfrac{4}{2} = \dfrac{6}{a} \neq \dfrac{11}{7}$$
$$a = 3$$
Hence, option C is correct.
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