If $$\frac{4}{x + y} + \frac{3}{x - y} = 2, \frac{8}{x + y} - \frac{1}{x - y} = \frac{1}{2}$$, then ($$x$$, y) =

A

(-5, -3)

B

(-3, -5)

C

(3, 5)

D

(5, 3)