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If diagonals of a rhombus are 12 cm and 16 cm, then what is the perimeter (in cm) of the rhombus?
Two diagonals of the rhombus are 12 cms and 16 cms (Given)
We know that,
The sides of the rhombus are congruent i.e sides have same length and
Two diagonals are perpendicular and bisect each other.
$$\therefore \angle AOB = 90^{\circ}$$ and
AB = $$\sqrt{6^{2} + 8^{2}} = \sqrt{36 + 64} = \sqrt{100} = 10$$
Now, perimeter = $$4(10) = 40$$
Hence, option B is the correct answer.
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