$$22^{2}+\sqrt{?}=529$$

Solution

Let the number to replace the question mark be equal to $$X$$

So, $$22^{2}+\sqrt{X}=529$$
Or, $$484 + \sqrt{X} = 529$$
Hence, $$\sqrt{X} = 45$$

Therefore, $$X = 45^2 = 2025$$

Hence, the correct option is option (c)

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