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If sum of smaller number x and two times the other number is equal to the sum of two times the smaller number and 16. The difference between the numbers is 6. Find the smaller number.
Let the smaller number be $$x$$ and the other number be $$y$$
Acc. to ques, => $$x + 2y = 2x + 16$$
=> $$2y - x = 16$$ -------------(i)
Also, difference between the numbers = $$y - x = 6$$ ------------(ii)
Multiplying eqn(ii) by 2 and then subtracting it from (i), we get :
=> $$(2y - 2y) + (-x + 2x) = 16 - 12$$
=> $$x = 4$$
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