Graduate female population of State B is what percent of the Graduate female population of State E ? (rounded off to nearest integer)

Total graduate population of state B = $$\frac{18}{100} \times 24$$ lakhs

=> Female graduates of state B = $$\frac{3}{8} \times \frac{18}{100} \times 24$$ lakhs

= $$9 \times 0.18 = 1.62$$ lakhs

Total graduate population of state E = $$\frac{20}{100} \times 24$$ lakhs

=> Female graduates of state E = $$\frac{7}{16} \times \frac{20}{100} \times 24$$ lakhs

= $$\frac{7}{2} \times \frac{3}{5} = 2.1$$ lakhs

$$\therefore$$ Required % = $$\frac{1.62}{2.1} \times 100$$

= $$77.14 \% \approx 77 \%$$