$$\frac{4 \cosec 150^\circ + 3 \sec^2 210^\circ}{5 \tan 225^\circ + 6 \cot^2 330^\circ} =$$

A

$$\frac{12}{23}$$

B

$$\frac{-12}{23}$$

C

$$\frac{7}{11}$$

D

$$\frac{-7}{11}$$