$${8^{1.1}} \times {4^2}^{.7} \times {2^{3.3}} = {2^?}$$

Solution

Expression : $${8^{1.1}} \times {4^2}^{.7} \times {2^{3.3}} = {2^?}$$

=> $$(2)^{3 \times 1.1} \times (2)^{2 \times 0.7} \times (2)^{3.3} = (2)^x$$

=> $$(2)^{3.3} \times (2)^{1.4} \times (2)^{3.3} = (2)^x$$

=> $$(2)^{3.3 + 1.4 + 3.3} = (2)^x$$

Comparing both sides, we get :

=> $$x = 3.3 + 1.4 + 3.3 = 8$$

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