Question 125

$$3 - \frac{3+\sqrt{5}}{4} - \frac{1}{3 + \sqrt{5}}$$

Solution

Expression : $$3 - \frac{3+\sqrt{5}}{4} - \frac{1}{3 + \sqrt{5}}$$

= $$3 - \frac{3+\sqrt{5}}{4} - [\frac{1}{3 + \sqrt{5}}\times(\frac{3-\sqrt5}{3-\sqrt5})]$$

= $$\frac{12-3-\sqrt5}{4}-(\frac{3-\sqrt5}{9-5})$$

= $$\frac{9-\sqrt5}{4}+ (\frac{-3+\sqrt5}{4})$$

= $$\frac{9-3-\sqrt5+\sqrt5}{4}=\frac{6}{4}=\frac{3}{2}$$

=> Ans - (B)


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