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Question 124
Out of six consecutive natural numbers, if the sum of first three is 27, what is the sum of the other three ?
Solution
let's say 6 consecutive numbers are (a-d), a, (a+d), (a+2d), (a+3d), (a+4d)
where d is the common difference i.e. 1 (given) and a is second term
summation of first three terms will be 3a = 27
hence second term a = 9
now sequence is 8,9,10,11,12,13,
so sum of last three terms 36
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