Question 124

A train moving at a rate of 36 km/hr. crosses a standing man in 10 seconds. It will cross a platform 55 metres long, in :

Solution

Let the length of train be y meter

speed of train = 36km/hr = 36 x $$\frac{5}{18}$$ = 10 m/sec

It crosses a man in 10 seconds . a train is assumed to cross a man when the train's back part fully crosses the man and hence

y = 10 x 10 = 100 meter

Platform length = 55 meter

time taken to cross a platform

(55 + 100) = 10 x T

T = 15 $$\frac{1}{2}$$ seconds

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