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The roots of the equation $$\sqrt{6} x^{2} - 5x + \sqrt{6} = 0$$ are
$$\sqrt{6}, \frac{1}{\sqrt{6}}$$
$$\sqrt{6}, \frac{-1}{\sqrt{6}}$$
$$\sqrt{\frac{2}{3}}, \sqrt{\frac{3}{2}}$$
$$\sqrt{\frac{2}{3}}, -\sqrt{\frac{3}{2}}$$
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