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The average marks of 14 students was 71. It was later found that the marks of one of the students has been wrongly entered as 42 instead of 56 and of another as 74 instead of 32. What is the correct average?
given that the average of 14 students is 71
so sum of the marks = 14*71
=>994
given that 42 is entered instead of 56 and 74 instead of 32
so 994+(56-42)-(74-32)
994+14-42=966
now the average is $$\frac{966}{14}=69$$
so, the correct average is 69
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