Instructions

What will come in place of the question mark (?) in the following questions ?

Question 123

$$\frac{12^2-4^2}{9^2-3^2}=?$$

Solution

Expression : $$\frac{12^2-4^2}{9^2-3^2}=?$$

= $$\frac{(12 - 4) (12 + 4)}{(9 - 3) (9 + 3)}$$

= $$\frac{8 \times 16}{6 \times 12}$$

= $$\frac{16}{9} = 1\frac{7}{9}$$


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