Question 123

A shopkeeper fixes the price of an article at 30% higher than its actual cost. If he sells it at 10% discount on marked price then, the profit is:

Solution

Let cost price = Rs. $$100$$

Markup % = 30%

=> Marked price = $$100+(\frac{30}{100}\times100)$$

= $$100+30=Rs.$$ $$130$$

Discount % = 10%

=> Selling price = $$130-(\frac{10}{100}\times130)$$

= $$130-13=Rs.$$ $$117$$

$$\therefore$$ Profit % = $$\frac{(117-100)}{100}\times100=17\%$$

=> Ans - (B)

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