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If $$3x^2 - 5x - 8 < 0$$, then x lies in the interval
$$\left(-1, \frac{8}{3}\right)$$
$$\left(\frac{-8}{3}, -1\right)$$
$$(-\infty, -1)$$
$$\left(\frac{8}{3}, \infty \right)$$
we have given that
$$3x^2 - 5x - 8 < 0$$,
now factorize the equation we get
$$3x^2 - 8x + 3x - 8 < 0$$
$$3x^2 + 3x - 8x - 8 < 0$$
so we get
(x + 1) (3x - 8) < 0
x = -1 , 8\3 answer
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