Two boys are on opposite sides of a tower of 80 meters height. They measures the angles of elevation of the top of tower as $$45^\circ$$ and $$60^\circ$$ respectively. The distance between two boys(in meters) is

A

$$\frac{80}{3} (3 + \sqrt{3})$$

B

$$\frac{80}{\sqrt{3}$$

C

$$\frac{80}{3} (\sqrt{3} - 1)$$

D

$$\frac{80}{3} (3 - \sqrt{3})$$