Question 123

The polynomial in x of least degree with the roots $$\frac{3}{2}, \frac{2}{3}, \pm \sqrt{3}$$ is

Solution

we have given that the root of the polynomonal equation

$$\frac{3}{2}, \frac{2}{3}, \pm$$ \sqrt{3}$$ is mean that

(x - 3\2 = 0 ) ( x - 2\3 = 0 ) ( x$$ \pm $$ $$\sqrt{3}$$ = 0 )

so we have (3x - 2) (2x - 3) ($$ x^{2}$$ - 3) = 0 is the equation so the

(3x - 2) (2x - 3) ($$ x^{2}$$ - 3) = 0 answer

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