$$\frac{4 \tan 150^{\circ} + \sin 240^{\circ}}{5 \cos 330^{\circ} + 3 \cot 225^{\circ}} = m + n\sqrt{3} \Rightarrow m + n$$ =

A

$$\frac{-11}{13}$$

B

$$\frac{11}{13}$$

C

$$\frac{-13}{11}$$

D

$$\frac{13}{11}$$