Seen from the top of a tower 100 meters tall the angles of depression of two points A and B on the ground which are on the opposite sides of the tower are $$30^{\circ}$$ and $$60^{\circ}$$ respectively. The distance AB in meters is:

A

$$400\sqrt{6}$$

B

$$400\sqrt{3}$$

C

$$\frac{400\sqrt{3}}{3}$$

D

$$\frac{400}{3}$$