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it is given that $$x + \frac{1}{x}$$ = 12
we need to find value of $$x^2 + \frac{1}{x^2}$$
$$x^2 + \frac{1}{x^2}$$ = $$(x + \frac{1}{x})^2$$ - 2
= $$12^2 - 2$$ = 142
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