If $$x + \frac{1}{x} = 12 $$, the value of $$x^2 + \frac{1}{x^2}$$ is
it is given that $$x + \frac{1}{x}$$ = 12
we need to find value of $$x^2 + \frac{1}{x^2}$$
$$x^2 + \frac{1}{x^2}$$ = $$(x + \frac{1}{x})^2$$ - 2
= $$12^2 - 2$$ = 142
Create a FREE account and get:
Day-wise Structured & Planned Preparation Guide
By proceeding you agree to create your account
Free CAT Schedule PDF will be sent to your email address soon !!!
