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Angle between the internal bisectors of two angles of a triangle ∠B and ∠C is 120°, then ∠A is
Given : $$\angle$$BPC = 120° and BP & CP are angle bisectors
=> $$\angle$$BPC = 90° + $$\frac{\angle A}{2}$$
=> $$\frac{\angle A}{2} = 30^{\circ}$$
=> $$\angle$$A = 60°
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