Question 121
Angle between the internal bisectors of two angles of a triangle ∠B and ∠C is 120°, then ∠A is
Solution
Given : $$\angle$$BPC = 120° and BP & CP are angle bisectors
=> $$\angle$$BPC = 90° + $$\frac{\angle A}{2}$$
=> $$\frac{\angle A}{2} = 30^{\circ}$$
=> $$\angle$$A = 60°
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
