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A man covers half of his journey by train at 90 km/hr, one-third of the remainder by bus at 30 km/hr and the rest by cycle at 10 km/hr. The average speed during the entire journey is ______
Average speed = Total distance/total time
Let us consider total distance =180km
Case 1 : man covers half of his journey by train at 90 km/hr
Distance= 90km => time t1=$$\frac{90}{90}$$=1hr
Remaining distance = 90km
Case 2 : man covers one-third of the remainder by bus at 30 km/hr
Distance = 30km => time t2=$$\frac{30}{30}$$=1hr
Case 3 : man covers rest by cycle at 10 km/hr
Distance = 60km => time t3=$$\frac{60}{10}$$=6hr
Therefore Average speed = $$\frac{180}{1+1+6}$$= 22.5km/hr
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