60 discs each of diameter 21 cm and thickness $$\frac{1}{3}$$ cm are stacked one above the other to form rightcircular cylinder.
What is its volume in $$m^3$$ if $$\pi = \frac{22}{7}$$?
Radius of cylinder = $$\frac{21}{2}$$ cm and height = $$\frac{1}{3}\times60=20$$ cm
Volume of cylinder = $$\pi r^2h$$
= $$\frac{22}{7}\times (\frac{21}{2})^2\times20$$
= $$22\times63\times5=6930$$ $$cm^3$$
= $$6.93\times10^{-3}$$ $$m^3$$
=> Ans - (D)
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