Question 120

A field is in the shape of a trapezium whoseparallel sides are 200 m and 400 m long, whereas each of other two sides is 260 m long. What is the area (in m$$^2$$)of the field?

Solution

Let ABCD be the trapezium and since the non parallel sides are equal, then CE = FD = 100 m

In right $$\triangle$$ ACE,

=> $$(AE)^2=(AC)^2-(CE)^2$$

=> $$(AE)^2=67600-10000$$

=> $$AE=\sqrt{57600}=240$$ m

$$\therefore$$ Area of trapezium = $$\frac{1}{2}h(AB+CD)$$

= $$\frac{1}{2}\times240\times(200+400)$$

= $$120\times600=72000$$ $$m^2$$

=> Ans - (C)

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