Question 120
A field is in the shape of a trapezium whoseparallel sides are 200 m and 400 m long, whereas each of other two sides is 260 m long. What is the area (in m$$^2$$)of the field?
Solution
Let ABCD be the trapezium and since the non parallel sides are equal, then CE = FD = 100 m
In right $$\triangle$$ ACE,
=> $$(AE)^2=(AC)^2-(CE)^2$$
=> $$(AE)^2=67600-10000$$
=> $$AE=\sqrt{57600}=240$$ m
$$\therefore$$ Area of trapezium = $$\frac{1}{2}h(AB+CD)$$
= $$\frac{1}{2}\times240\times(200+400)$$
= $$120\times600=72000$$ $$m^2$$
=> Ans - (C)
Get AI Help
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
