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Question 120
A and B together can complete a particular task in 4 days.If A alone can complete the same task in 6 days, how many days will B take to complete the task if he works alone ?
Solution
Let the piece of Work be W.
Let the speed of A be x and that of B be y.
Now, together they can complete the work in 4 days.
W/(x+y) = 4, W = 4x + 4y
A alone can complete in 6 days.
W/x = 6, W = 6x.
On substituting value of W in terms of x, we get
x = 2y
y = x/2
The speed of B is half of A.
B will complete the work in 12 days.
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