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Question 12

The equivalent resistance between $$A$$ and $$B$$ of the network shown in figure

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Solution

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(Balanced Wheatstone bridge)

$$\frac{1}{R_{\text{eq}}} = \frac{1}{4R} + \frac{1}{8R}$$

$$\frac{1}{R_{\text{eq}}} = \frac{3}{8R}$$

$$R_{\text{eq}} = \frac{8R}{3}$$

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