Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
Let $$\sigma$$ be the uniform surface charge density of two infinite thin plane sheets shown in figure. Then the electric fields in three different region $$E_I, E_{II}$$ and $$E_{III}$$
Field due to one infinite charged sheet is
$$E=\frac{\sigma}{2\epsilon_0}$$and is directed away from the sheet.
Region I:
Both sheets produce field toward left.
$$E_I=\frac{\sigma}{2\epsilon_0}+\frac{\sigma}{2\epsilon_0}$$
$$E_I=\frac{\sigma}{\epsilon_0}$$
Region II:
Field due to left sheet is rightward and due to right sheet is leftward, equal in magnitude, so they cancel.
$$E_{II}=0$$
Region III:
Both fields are rightward.
$$E_{III}=\frac{\sigma}{2\epsilon_0}+\frac{\sigma}{2\epsilon_0}$$
$$E_{III}=\frac{\sigma}{\epsilon_0}$$
Thus,
$$E_I=E_{III}=\frac{\sigma}{\epsilon_0},\quad E_{II}=0$$
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.