Sign in
Please select an account to continue using cracku.in
↓ →
p, q and r are three non-negative integers such that p + q + r = 10. The maximum value of pq + qr + pr + pqr is
The product of 2 numbers A and B is maximum when A = B.
If we cannot equate the numbers, then we have to try to minimize the difference between the numbers as much as possible.Β
pq will be maximum when p=q.
qr will be maximum when q=r.
qr will be maximum when r=p.
Therefore, p, q, and r should be as close to each other as possible.Β
We know that p,q,and r are integers and p+q+r=10.
=> p,q, and r should be 3,3, and 4 in any order.Β
Substituting the values in the expression, we get,Β
pq+qr+pr+pqr = 3*3 + 3*4 +Β 3*4 + 3*3*4
= 9 + 12 +Β 12 + 36
= 69
Therefore, option C is the right answer.
Click on the Email βοΈ to Watch the Video Solution
Educational materials for CAT preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.