Four number-pairs have been given, out of which three are alike in some manner and oneisdifferent. Select the number-pair thatis different.
In 169 - 197,
$$(13)^2$$ = 169
$$(14)^2 +Â 1$$ = 196 +Â 1 = 19
In 121-145,
$$(11)^2$$ = 121
$$(12)^2 + 1$$ = 144 + 1 = 14
In 289-325,
$$(17)^2$$ = 289
$$(18)^2 + 1$$ = 324 + 1 = 32
In 225-241
$$(15)^2$$ = 225
$$(16)^2 - 15Â $$ = 256 - 15 = 241
$$\therefore$$ The correct answer is option D.
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