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If $$13 \sin \theta = 12$$ and $$\theta$$ acute, then $$\frac{cosec \theta + \cot \theta}{\tan \theta + \sec \theta} =$$
$$\frac{3}{8}$$
$$\frac{3}{10}$$
$$\frac{10}{3}$$
$$\frac{8}{3}$$
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