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$$\tan 960^{\circ} + \cos 510^{\circ} + \sec 750^{\circ} =$$
$$\frac{7 -\sqrt{3}}{2\sqrt{3}}$$
$$\frac{10 -\sqrt{3}}{2\sqrt{3}}$$
$$\frac{7}{2\sqrt{3}}$$
$$\frac{13}{2\sqrt{3}}$$
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