If $$\theta$$ is not in the third quadrant and $$\cos \theta = \frac{-4}{5}$$, then $$\frac{3\tan \theta + 5\cosec \theta}{4\cot \theta + 3 \sec \theta}=$$

A

$$\frac{-24}{79}$$

B

$$\frac{-77}{119}$$

C

$$\frac{-73}{109}$$

D

$$\frac{-29}{71}$$