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If $$\sqrt{3} \sec 510^{\circ} - \tan 480^{\circ} + \cot 765^{\circ} = \sqrt{x} - y$$, then the quadratic equation with roots $$\sqrt{x} - y$$ and $$\sqrt{x} + y$$
$$x^{2} - \sqrt{3x} - 3 = 0$$
$$x^{2} + 2\sqrt{3x} + 2 = 0$$
$$x^{2} - 2\sqrt{3x} + 2 = 0$$
$$2x^{2} - \sqrt{3x} + 1 = 0$$
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