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If $$\sin \theta = \frac{1}{2}$$ and $$\theta \epsilon \left[\frac{\pi}{2}, \frac{3 \pi}{2}\right]$$, then $$4 \theta = $$
$$\frac{-2 \pi}{3}$$
$$\frac{2 \pi}{3}$$
$$\frac{10 \pi}{3}$$
$$\frac{14 \pi}{3}$$
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