If $$\frac{48}{x+y}-\frac{6}{x-y} =10$$ and $$\frac{15}{x+y}+\frac{4}{x-y} =9$$, then $$(x,y)=$$

A

(1, 2)

B

(-1, - 2)

C

(2, 1)

D

(- 2, -1)