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Question 117
The sum of two numbers is 37 and the difference of their squares is 185, then the difference of the two numbers is
Solution
Let the numbers be $$x$$ and $$(37-x)$$
According to ques,
=> $$(37-x)^2-(x)^2=185$$
Using, $$a^2-b^2=(a-b)(a+b)$$
=> $$(37-x-x)(37-x+x)=185$$
=> $$(37-2x)(37)=185$$
=> $$37-2x=\frac{185}{37}=5$$
=> $$2x=37-5=32$$
=> $$x=\frac{32}{2}=16$$
Thus, second number = $$37-16=21$$
$$\therefore$$ Difference of the two numbers = $$21-16=5$$
=> Ans - (A)
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