Question 116
The angle of depression of a point situated at a distance of 70 m form the base of a tower is $$60^\circ$$. The height of tower is:
Solution
AB is the tower = $$h$$ =Â ?
In $$\triangle$$ ABC,
=> $$tan(60^\circ)=\frac{AB}{BC}$$
=> $$\sqrt{3}=\frac{h}{70}$$
=> $$h=70\sqrt{3}$$ m
=> Ans - (A)
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