Question 116

The angle of depression of a point situated at a distance of 70 m form the base of a tower is $$60^\circ$$. The height of tower is:

Solution

AB is the tower = $$h$$ = ?

In $$\triangle$$ ABC,

=> $$tan(60^\circ)=\frac{AB}{BC}$$

=> $$\sqrt{3}=\frac{h}{70}$$

=> $$h=70\sqrt{3}$$ m

=> Ans - (A)


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