For how many integral values of 'x' sin $$\ \phi=\frac{3x-2}{4}$$, where $$0^{0}\leq\phi\leq90^{0}$$
$$0^{0}\leq\phi\leq90^{0}$$
=> $$0\leq sin\phi\leq1$$
=> $$0\leq (\frac{3x-2}{4})\leq1$$
=> $$0\leq(3x-2)\leq4$$
=> $$2\leq3x\leq6$$
=> $$\frac{2}{3}\leq x\leq2$$
Thus, integral values of $$x$$ =Â 2Â (1 and 2)
=> Ans - (A)
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