Question 116

Salary of A is 20% more than B and salary of B is 18% more than C. The salary of C is (approximately) how much percent less than A ?

Solution

Let B's salary = Rs. $$100$$

=> A's salary = $$100+\frac{20}{100}\times100=Rs.$$ $$120$$

=> C's salary = $$\frac{100}{(100+18)}\times100\approx Rs.$$ $$84.75$$

$$\therefore$$ Required % = $$\frac{(120-84.75)}{120}\times100=29.3\%$$

=> Ans - (A)

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