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For the two given equations I and II----
$$3p^2+2p-1 = 0$$
$$(3p-1)(p+1) = 0$$
$$p = -1, \frac{1}{3}$$
$$2q^2+7q+6 = 0$$
$$(2q+3)(q+2) = 0$$
$$q = -2, -\frac{3}{2}$$
p > q
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