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For the two given equations I and II----
I. $$3p^{2}+2p-1=0$$ II. $$2q^{2}+7q+6=0$$
Give answer (A) if p is greater than q.
Give answer (B) if p is smaller than q.
Give answer (C) if p is equal to q.
Give answer (D) if p is either equal to or greater than q.
Give answer (E) if p is either equal to or smaller than q.
$$3p^2+2p-1 = 0$$$$(3p-1)(p+1) = 0$$$$p = -1, \frac{1}{3}$$
$$2q^2+7q+6 = 0$$$$(2q+3)(q+2) = 0$$$$q = -2, -\frac{3}{2}$$
p > q
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