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For the two given equations I and II----
I. $$6p^{2}+5p+1=0$$ II. $$20q^{2}+9q=-1$$
Give answer (A) if p is greater than q.
Give answer (B) if p is smaller than q.
Give answer (C) if p is equal to q.
Give answer (D) if p is either equal to or greater than q.
Give answer (E) if p is either equal to or smaller than q.
$$6p^2+5p+1 = 0$$$$(2p+1)(3p+1) = 0$$$$p = -\frac{1}{2}, -\frac{1}{3}$$
$$20q^2+9q+1 = 0$$$$(4q+1)(5q+1) = 0$$$$q = -\frac{1}{4}, -\frac{1}{5}$$
$$p < q$$
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