Let N be theset of all natural numbers and $$f : N \rightarrow N$$ be defined by f(n) = r, where r is the remainder when n is divided by 17 for any $$n \epsilon N$$. Then $$\left\{n \epsilon N: f(n) = 3 \right\} =$$

A

$$\left\{3}\right\$$

B

$$\left\{17k + 3: k = 0, 1, 2, 3, ... ... ...\right}$$

C

$$\left\{3k + 17: k = 0, 1, 2, 3, ... ... ...\right}$$

D

$$\left\{17k + 3: k = 0, \pm 1, \pm 2, \pm 3, ... ... ...\right}$$