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Among the following, the converse of $$p \rightarrow (q \rightarrow r)$$ is equivalent to
$$(p \vee q) \wedge (r \rightarrow p)$$
$$\sin r \vee (p \wedge q)$$
$$(r \rightarrow q) \rightarrow p$$
$$(p \wedge q) \vee (r \rightarrow p)$$
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