If $$27x^{3} - 54x^{2} + 36x - 8 = 0$$, then $$(x^{2} +  \frac{1}{x^{2}}) + 4(x +\frac{1}{x}) + 3$$ =

A

$$\frac{421}{36}$$

B

$$\frac{473}{36}$$

C

$$\frac{503}{36}$$

D

$$\frac{517}{36}$$