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If $$27x^{3} - 54x^{2} + 36x - 8 = 0$$, then $$(x^{2} + \frac{1}{x^{2}}) + 4(x +\frac{1}{x}) + 3$$ =
$$\frac{421}{36}$$
$$\frac{473}{36}$$
$$\frac{503}{36}$$
$$\frac{517}{36}$$
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