$$\frac{\frac{126}{14}\times?-7\times3}{8^{2}-7\times6+20}=1$$

Solution

Expression : $$\frac{\frac{126}{14}\times?-7\times3}{8^{2}-7\times6+20}=1$$

=> $$\frac{9x - 21}{64 - 42 + 20} = 1$$

=> $$9x - 21 = 42$$

=> $$9x = 42 + 21 = 63$$

=> $$x = \frac{63}{9} = 7$$

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