A can finish a work in 18 days and B can do the same work in 5 days. B worked for 2 days and left the job. In how many days, A alone can finish the remaining work?

Let the amount of work be 90 units (which is LCM of 5 and 18)

It is given that A complete 90 units of work in = 18 days

A's 1 day work = 5 units

Given that B completes 180 units of work in = 5 days

B's 1 day work = 18 units

B worked for 2 days then the amount of work done by him = 18 x 2 = 36 units

Units of work left = 90 - 36 = 54 units

Now time taken by A to complete the remaining work = $$\frac{54}{5}$$ = 10.8 days