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Let N denote the set of natural numbers. Define
$$A = \left\{ x \mid x = 4n, n ∈ N\right\} and B = \left\{ x \mid x = 6n, n ∈ N\right\}$$ then $$A \cap B = $$
$$\left\{ x \mid x = 24n, n ∈ N\right\}$$
$$\left\{ x \mid x = 12n, n ∈ N\right\}$$
$$\left\{ x \mid x = 2n, n ∈ N\right\}$$
The empty set
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